4-7x=3-4x-(8/4(4+2^2)+3x)

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Solution for 4-7x=3-4x-(8/4(4+2^2)+3x) equation: 



4-7x=3-4x-(8/4(4+2^2)+3x)

We move all terms to the left:

4-7x-(3-4x-(8/4(4+2^2)+3x))=0



Domain of the equation: 4(4+2^2)+3x))!=0

x∈R



We multiply all the terms by the denominator


-7x*4(4+2^2)+3x))-(3-4x-(8+3x))+4*4(4+2^2)=0

We add all the numbers together, and all the variables

-7x*4(4+2^2)+3x))-(3-4x-(3x+8))+4*4(4+2^2)=0

We add all the numbers together, and all the variables

-7x*4(4+2^2)+3x))-(3-4x-(3x=0

Wy multiply elements

-28x^2(4+3x))-(3-4x-(3x=0

We add all the numbers together, and all the variables

-28x^2(3x+4))-(3-4x-(3x=0

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